Primary 6 · Volume · Question type 7.6

P6 Volume: Pouring Water Between Two Containers

The water keeps the same volume; divide that volume by its depth to find the new base area.

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Primary 6, on the MOE Primary Mathematics syllabus.

In the Volume chapter7 question types · see the chapter

The lesson · 2 minutes 41 seconds

How do you solve P6 volume questions about pouring between containers?

Watch: one tenth of a full cubical tank poured into an empty one

Another worked example

A worked example

Tank A is a cubical tank of edge 20 cm, completely full of water. Water is poured out of Tank A until it is 12 cm deep, and all the poured water goes into the empty Tank B, which has a square base. After that, the depth of the water in Tank A to the depth of the water in Tank B is 6 : 1. Find the length of one side of Tank B's square base.

The working · Six lines

The step-by-step working

Written out in full, the way it should appear on paper.

base area of A = 20 × 20 = 400
water left in A = 400 × 12 = 4800
volume poured = 8000 - 4800 = 3200
depth in B = 12 ÷ 6 = 2
base area of B = 3200 ÷ 2 = 1600
side of base = √1600 = 40 cm

The answer is 40 cm.

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Find the large bottle’s capacity

Find the amount of syrup, then use the shortfall to find the capacity.

All the syrup in a jug was poured into one large bottle. It was 180 ml short of filling the large bottle to the top. The same jug of syrup would instead have filled one small bottle to the top and left 220 ml over. A small bottle holds 500 ml. Find the capacity of the large bottle.

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syrup = 500 + 220 = 720
large bottle = 720 + 180 = 900 ml

Ans: 900 ml

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