Two-step word problems and matching units

A florist had one thousand two hundred and sixty roses. She used three hundred and ninety-six of them for a wedding and tied the rest into bunches of 8. How many bunches did she tie? Try it first. Pause if you like. Only the roses left after the wedding go into bunches. What must we find first? Start with one thousand two hundred and sixty roses. Three hundred and ninety-six were used for the wedding. Roses left: one thousand two hundred and sixty minus three hundred and ninety-six equals eight hundred and sixty-four. Eight hundred and sixty-four counts the roses still available. This is the total we can put into bunches. Each bunch uses 8 of the remaining roses. Which number must we divide? Carry the number of roses left into the next step. How many groups of 8 fit into eight hundred and sixty-four? Set out the long division. 8 times 1 is 8, so it fits. 8 times 2 is 16, too big for 8. So 1 is the biggest that fits. Write 1 in the hundreds place. Eight times one is eight. Eight minus eight leaves zero. Bring down the 6 tens. We now have 6 tens to divide by 8. 8 times 0 is 0, so it fits. 8 times 1 is 8, too big for 6. So 0 is the biggest that fits. Write 0 in the tens place. Eight times zero is zero. Six minus zero leaves six. Bring down the 4 ones beside the 6. Now we have 64 ones. 8 times 8 is 64, so it fits. 8 times 9 is 72, too big for 64. So 8 is the biggest that fits. Write 8 in the ones place. Eight times eight is sixty-four. Sixty-four minus sixty-four leaves zero. Eight hundred and sixty-four divided by 8 is one hundred and eight bunches. She tied one hundred and eight bunches. First subtract the roses used, then group only the rest. The second step uses the answer from the first.

A sack holds 5 kilograms of rice. The rice is repacked into packets of two hundred and fifty grams each. How many packets are there? Try it first. Pause if you like. Both masses must be in the same unit before we divide. What do we need first? The sack holds 5 kilograms. Each packet holds two hundred and fifty grams. 5 kilograms is five thousand grams. The mass has not changed. We have written it in grams, to match the packets. We know the total mass in grams. Which number goes into the division? Carry the five thousand grams into the next step. How many groups of two hundred and fifty fit into five thousand? Set out the long division. Two hundred and fifty is greater than five and than fifty, so start with five hundred. Two hundred and fifty times 2 is five hundred, so it fits. Two hundred and fifty times 3 is seven hundred and fifty, too big for five hundred. So 2 is the biggest that fits. Write 2 in the tens place. 2 times two hundred and fifty is five hundred. Subtract five hundred, leaving zero. Bring down the last zero. There are zero ones left to divide. Two hundred and fifty times 0 is 0, so it fits. Two hundred and fifty times 1 is two hundred and fifty, too big for 0. So 0 is the biggest that fits. Write 0 in the ones place. Two hundred and fifty times zero is zero. Zero minus zero leaves zero. Five thousand divided by two hundred and fifty is 20 packets. There are 20 packets. Convert first, then divide using matching units. Find one thing at a time. Label it, then use its answer in the next step.