One group at a time
P4 grouping problems: work with repeating bundles, distinguish paid items from free items and connect equal gaps with the objects at their ends.
Questions in this lesson
Transcript
Ravi buys some pens and files. A pen costs 2 dollars and a file costs 5 dollars. He buys 3 times as many pens as files. He pays 66 dollars altogether. How many pens does he buy? Try it first. Pause if you like. For every file, Ravi buys 3 pens. So put 3 pens and 1 file together in one group. 3 pens cost 3 times 2, which is 6 dollars. Add the file. One group costs 6 plus 5, which is 11 dollars. Ravi pays 66 dollars. 66 divided by 11 is 6, so there are 6 groups. Each group has 3 pens. 6 times 3 is 18. So Ravi buys 18 pens.
A bakery gives 1 free bun for every 4 buns bought. Ali takes home 35 buns, all in full offer groups. Each bun costs 2 dollars. How much does Ali pay? Try it first. Pause if you like. For every 4 buns Ali pays for, he gets 1 more bun free. So one offer group has 4 plus 1, which is 5 buns. Ali takes home 35 buns. 35 divided by 5 is 7, so there are 7 offer groups. In every group, Ali pays for 4 buns. 7 times 4 is 28 buns. Each bun costs 2 dollars. 28 times 2 is 56. So Ali pays 56 dollars altogether. Find what one group holds or costs, then count how many groups there are.