The idea in brief. Cut the figure into rectangles to find its AREA, and slide its sides out to the rectangle that encloses it to find its PERIMETER; the only sides that do not slide are the two edges of a notch, and those are added on.
Lesson video, with the working
Perimeter of staircase and notched figures
4 min 05 s
The film teaches 2 questions in turn. Each question shows first; its working is written as the film explains it.
In the figure below all the lines meet at right angles. Going down from the top left, the figure steps across 6 cm, down 4 cm, across 5 cm, down 3 cm, across 7 cm and down 5 cm before the base runs back to the left-hand side. Find the perimeter of the figure.
Length of the figure = 6 cm + 5 cm + 7 cm = 18 cm
Breadth of the figure = 4 cm + 3 cm + 5 cm = 12 cm
Perimeter = 18 cm + 12 cm + 18 cm + 12 cm = 60 cm
Ans: 60 cm
Example 1
The figure below is a rectangle 22 cm long and 14 cm wide with a notch cut into its bottom edge. The notch is 6 cm wide and 5 cm deep, and all the lines meet at right angles. Find the perimeter of the figure.
Perimeter of the enclosing rectangle = 22 cm + 14 cm + 22 cm + 14 cm = 72 cm
Perimeter of the figure = 72 cm + 5 cm + 5 cm = 82 cm
Ans: 82 cm
How to solve it
Follow the whole outside boundary, including sides without labels.
For a staircase, combine the across-steps: 6 plus 5 plus 7 is 18 centimetres.
Combine the down-steps: 4 plus 3 plus 5 is 12 centimetres. The shifted edges keep their lengths.
Perimeter is 18 plus 12 plus 18 plus 12, which is 60 centimetres.
For a notch, first find the enclosing rectangle perimeter: 22 plus 14 plus 22 plus 14 is 72 centimetres.
Add both extra depths: 72 plus 5 plus 5 is 82 centimetres. The horizontal notch edge already fills the bottom gap.
A staircase shifts into the enclosing rectangle. A notch leaves two extra depths to include.
Practice questions with worked solutions
Question 1 is free to try. The other 7 open in the free trial, each with its full working.
Cut the figure into Rectangle A on top and Rectangle B below.
Area of A = PQ × QR = 9 cm × 5 cm = 45 cm²
ST = UP - QR = 13 cm − 5 cm = 8 cm
Area of B = TU × ST = 16 cm × 8 cm = 128 cm²
Area of the figure = 45 cm² + 128 cm² = 173 cm²
The area of the figure is 173 cm².
Answer: 173 cm²
For parents
How can I explain composite figures to my child?
Composite figures in the Primary 4 syllabus are made up of rectangles and squares.
What your child learns here
Composite figures in the Primary 4 syllabus are made up of rectangles and squares. Your child uses those familiar shapes to understand a larger outline, deciding which lengths must be found before calculating its area or perimeter. The important distinction is between dividing the surface into useful parts and following the boundary: an internal dividing line helps with area but is not automatically part of the perimeter.
Recover a missing horizontal or vertical length by comparing aligned totals and the shorter lengths that make them up.
Find area by adding non-overlapping rectangle or square areas, with every part of the required surface counted once.
Use an enclosing rectangle minus a rectangular cut-out when those dimensions describe the figure more directly.
Trace every exposed boundary segment for perimeter, including inward turns around a notch, while excluding internal joins.
Does the answer make sense?
When a composite figure is an enclosing rectangle with a non-empty rectangular piece removed, its area must be smaller than the enclosing rectangle's area. Your child can add the removed piece's area back to the proposed answer; the result should equal the whole rectangle, with all three areas using the same square unit.
How to practise these questions
Basic practice finds the area of a figure formed from rectangles. Intermediate questions introduce notches, corner cut-outs, an unknown side from perimeter and a folded sheet cut through more than one layer. The Challenge questions use equal-side marks, a piece cut and rejoined, an unchanged corner-cut perimeter or a total that includes internal panels. Ask your child to identify whether the required quantity follows the outside boundary, covers the remaining surface or includes extra internal lengths. For folded paper, account for the layers before calculating the area left. Reviewing which segments or regions were included is especially useful here, because correct arithmetic cannot repair a total that describes a different part of the figure.
Questions parents ask
Should my child add rectangles or subtract a cut-out? Either approach can work if the chosen parts describe the required surface exactly. Compare the available dimensions: a split may give two easily measured rectangles, while an outer rectangle and one cut-out may need fewer steps. Ask your child to name the regions being counted before calculating, so any overlap or omitted part becomes easier to notice.
Why can we add areas but not simply add perimeters? Areas of adjoining pieces add when their interiors do not overlap. Their separate perimeters include the shared join twice, although that join is inside the combined figure. Your child therefore needs the outside boundary of the combined shape. Tracing that boundary continuously is a useful way to decide which lengths belong in the final total.
Does removing a corner always change the perimeter? A rectangular corner cut-out can replace two removed outer segments with two new segments of the same total length, leaving the perimeter unchanged. A notch cut into the middle of an edge behaves differently because it adds inward and outward edges. Your child should follow the actual outline rather than apply one rule to every removed rectangle.